mutual authentication in STS protocol Posted by Hedeesa, at crypto.stackexchange.com, 28 Nov 2021 STS Protocol is like this: $A \rightarrow B:~ g^x$ $A \leftarrow B:~ g^y, E_K(S_B(g^y, g^x))$ $A \rightarrow B:~ E_K(S_A(g^x, gā¦